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$ \delta $-electrons and the Si detector

One of the first problems encountered is that of the $ \delta $-electron contamination of the detector. The $ \delta $-electrons are copiously produced by the $ Pb$ beam nuclei passing through the $ Pb$ target. The thickness of the target is 1.15 $ g/cm^2$, or 18% of the radiation length. Due to the $ z^2$ dependence of the ionization energy loss on the charge of the projectile, a passage of a beam nucleus without nuclear interaction (statistically, the predominant event) produces, typically, more $ \delta $-electrons than originate from (even a central) interaction. Kinematically, the problem is that of an elastic scattering of a relativistic heavy incident nucleus on an (effectively resting) atomic electron - a particular case of a relativistic elastic two-body scattering (analyzed in [75] and other textbooks). For an electron initially at rest in the lab, the dependence of its final state energy on the emittance angle $ \theta$ is unique, and there is no kinemitical restriction on the angle. The differential cross-section

$\displaystyle \frac{\,d\sigma}{\,d\theta} \propto \frac{\sin \theta}{\sqrt{1-\sin^2\theta}}$ (54)

grows with the polar angle for the angles of interest ( $ \theta<\pi/2$). This results in a peculiar pattern of detector occupancy, with maximum occupancy at the outer rings of the detector - opposite to the trend seen in the nuclear interactions. In valid beam triggered runs (I looked at both field polarities, to disentangle effects of $ \delta $-electrons from those of the geometrical misalignment) it was noticed that in the outer rings, the extra multiplicity on the outer rings, ascribed to the $ \delta $-electrons, is comparable with the contribution of the nuclear interaction vertex. In the T0-amplitude triggered [*]runs without magnetic field, $ \delta $-electrons dominate the picture. In this situation, we decided to In the 4 $ GeV/c$ setting, the magnetic field strength in the first dipole (which includes the target area) is $ \approx 0.8 Tl$. The kinetic energy spectrum of $ \delta $- electrons falls off like

$\displaystyle \frac{\,dN}{\,d(T/m_e)} \propto \Big(T/m_e\Big)^{-2}$ (55)

Simple estimates, based on the kinetic energy spectrum (as well as GEANT simulations) lead to the conclusion that for all practical purposes the residual contribution of $ \delta $-electrons to the multiplicity on the $ \delta $-clean side is negligible for the field and geometry in question.
next up previous contents
Next: Amplitude calibration of the Up: Technique for event-by-event multiparticle Previous: Data sample and data   Contents
Mikhail Kopytine 2001-08-09